if log6 to the base a = x and log3 to the base a = y.write log a/2 tothe base a in terms of x and y
Answers
Answered by
2
subtract log6 a and log3 a
log6 a -log3 a =x-y
use concept of logarithm
logX y-logZ y=logX/Z y
hence here,
log6 a -log3 a =x-y
log2 a=(x-y)
know question ask,
log(a/2) a=loga a -log2 a=1-(x-y)=1-x+y
(here log6 a means log6 base a in all cases)
log6 a -log3 a =x-y
use concept of logarithm
logX y-logZ y=logX/Z y
hence here,
log6 a -log3 a =x-y
log2 a=(x-y)
know question ask,
log(a/2) a=loga a -log2 a=1-(x-y)=1-x+y
(here log6 a means log6 base a in all cases)
Answered by
1
mark brainliest if you re satisfied
Attachments:
prathap12345:
I'm satisfied but ive already marked another answer as brainliest
Similar questions