Question

If log9 x + log3 x =6 then →
(1/2 )t² =((1/2) t + 3)(3)
(a) 81
(b) 9
(C) 3
(d) 27​

Answer 1

Step-by-step explanation:

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Answer 2

logb^n (a^m) =(m/n)logb(a)

(1/2)log3(x)+log 3(x) =6

(3/2)log 3(x) = 6

log 3(x) = 6*2/3

log 3(x) = 4 = 3^4= 81 = x

hence that the value of x = 81