Question

if loga=1/2logb=1/5logc the valye of a⁴b³c-²​

Answer 1

Answer:answer is 1

Step-by-step explanation:

Let,

loga=1/2logb=1/5logc=logK (some constant)

Then,

Loga=logK=> a=K

And, 1/2logb =logK=> log(b^1/2)=logK=> b^1/2 = K i.e. b=k^2

also,1/5logc=logK=>log (c^1/5)=logK=>c^1/5=K i.e. c=K^5

Now we have to find a^2b^3c^-2

Since, a= k, b=K^2, c=K^5

Therefore, a^2b^3c^-2= k^2k^6k^-10=1

Hope you understand

Answer 2

Answer:

a⁴b³c-² = 1

Step-by-step explanation:

Property Used

a^p × a^ q = a^p+q

a^-p = 1/a^p