Question

If loga/2=logb/3=logc/5, then bc =

Answer 1

•If loga/2=logb/3=logc/5 = k

then

loga/ 2= k

loga = 2k

loga = 2k × log 10

loga = log (10)^2k

a= 10^2k

and thus

logb/3 = k

logb = 3k

log b = log (10)^3k

b= 10^3k

and logc/5 = k

log c = 5k

log c = log (10)^5k

c= (10)^5k

bc= (10)^3k ×(10)^5k= (10)^8k= [(10)^2k]^4 = a^4(ans)