If Logx (1 / 8) = - 3 / 2, then x is equal to
A. - 4
B. 4
C. 1 / 4
D. 10
Answers
Answered by
1
it means that x^(-3/2) = 1/8 ( x^y -denotes x to the power y)
so as x^(-y) = 1 / (x^y)
x^(3/2) = 8
Now take the power to the other side(in simplistic terms)
=> x = 8^(2/3) = (8^(1/3))^ 2 = 2^2 = 4
so x = 4
so as x^(-y) = 1 / (x^y)
x^(3/2) = 8
Now take the power to the other side(in simplistic terms)
=> x = 8^(2/3) = (8^(1/3))^ 2 = 2^2 = 4
so x = 4
Answered by
0
Answer:
option a is correct
If Logx (1 / 8) = - 3 / 2, then x is equal to
Rewrite the logarithmic equations using exponential equation
x^logx(1/8)=x^-3/2
1/8=x^-3/2
8=x^3/2
cube root on both sides
2=x^1/2
x=2^2=4
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