If logx(1 / 8) = -3 / 4, than what is x?
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Given logarithmic form logx ( 1/8) = -3/4
Exponential form = x ^ -3/4 =1/8
x^-3/4*-4/3 =[1/8 ]^-4/3
x ^ 1 = 2^3*4/3
x = 2^4=16.
Exponential form = x ^ -3/4 =1/8
x^-3/4*-4/3 =[1/8 ]^-4/3
x ^ 1 = 2^3*4/3
x = 2^4=16.
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