Question

if,. logx-log√x=2/logx. then x=?

Answer 1

$given \\ log(x) - log( \sqrt{x} ) = \frac{2}{ log(x) } \\ log( \frac{x}{ \sqrt{x} } ) = \frac{2}{ log(x)}$
$log( \sqrt{x} ) = \frac{2}{ log(x) } \\ \frac{1}{2} log(x) = \frac{2}{ log(x) } \\ {( log(x)) }^{2} = 4 \\ log(x) = 2 \: \: \: or \: \: \: - 2$
$x = {10}^{2} \: \: \: or \: \: \: {10}^{ - 2} \\ x = 100 \: \: \: or \: \: \: 0.01$