Question

If logx(xy) a, then find the value of log)(xy)
O a/(a 1
a/(a+1)
(a-1)/a
0 l/a​

Answer 1

Answer:

(a-1)/a

is your right answer

please mark me as a brainleast

Answer 2

Answer:

If logx(xy) a, then find the value of log)(xy)

a/(a-1)

Step-by-step explanation:

concept used :

$log_{M}N$=$log_{a}N/log_{a}M$

log(MN)=log(M)+log(N)

Calculation:

$log_{xy}=a$

log(xy)/log(x)=a

log(x)+log(y)/log(x)=a

1+log(y)/log(x)=a

log(y)/log(x)=a-1

log(x)/log(y)=1/a-1

Add 1 to both sides and solving get,

log(x)/log(y)+1={a/(a-1)}+1

{log(x)+log(y)}/log(y)=(1+a-1)/a-1

log(xy)/log(y)=a/a-1

$log_{y}(xy)$ is equal to a/(a-1)

The project code is #SPJ2