Math, asked by debismitanaik214, 4 months ago

(o) 6y' - 3ys + 4y³ + 8y÷3y

Answers

Answered by chinmayeeallu
0

Answer:

hope this helps you alot

Step-by-step explanation:

6y-3y+4y³+8y÷3y

3y-4y³+(8/3)y

4y³-(17/3)y

Answered by ItzDinu
4

 \huge \mathscr{\orange {\underline{\red{\underline {Answer:-}}}}}

= 6y - 3y + 4y³ + 8y÷3y

= 18y⁵ - 3y

= 15y⁴ ÷ 3y

= 5y³

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