Question

If LPG cylinder contains mixture of butane and isobutane, then the amount of oxygen that would
required for combustion of Ikg of it will be-
(1) 1.8 kg
(2) 2.7 kg
(3) 4.5 kg
(4) 3.58 kg​

Answer 1

Answer:

#pls thank and rate

Explanation:

Butane and isobutane have same molecular formula C4H10

C4H10+132O2→4CO2+5H2O

58g C4H10 requires O2=132×32g

∴1000gC4H10 requires O2=13×32×10002×58

⇒358.62g

Or 3.586kg

Hence (d) is the correct option.

Answer 2

Answer:

3.58kg

Explanation:

#@ plz thank rate me

butane and isobutane have same molecular weight formula

C4H10

C4H10 + 132O2= 4CO2 + 5H2O

58g C4H10 requires O2= 132×32

1000 C4H10

O2 =13×32×10002×58

358.62g

(or)

3.586kg