If π<2x<3π/2 , then
√{2+√(2+2cos4x)}
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lastly it is equals to
+- 2cos theta
now since pi <2theta< 3pi/2..or pi/2 <theta <3pi/4..or 90 <theta <135....so between this range of theta ,cos theta will be negative so the above solution will be equal to -2cos theta
+- 2cos theta
now since pi <2theta< 3pi/2..or pi/2 <theta <3pi/4..or 90 <theta <135....so between this range of theta ,cos theta will be negative so the above solution will be equal to -2cos theta
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aryanrockz64oyb3yj:
Thanks
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