If m^2 +1,m^2 - 1 and 2m form a pythagorean triplet for all m >1 then what are the measure of pythagorean triplet for m =3
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Hi ,
If m = 3 ,
m² + 1 = 3² +1 = 9 + 1 = 10
m² - 1 = 3² - 1 = 9 - 1 = 8
2m = 2 × 3 = 6
Therefore ,
Required triplet = ( 6 , 8 , 10 )
I hope this helps you.
:)
If m = 3 ,
m² + 1 = 3² +1 = 9 + 1 = 10
m² - 1 = 3² - 1 = 9 - 1 = 8
2m = 2 × 3 = 6
Therefore ,
Required triplet = ( 6 , 8 , 10 )
I hope this helps you.
:)
shreya204:
Wow thank you for clearing my doubt
Very nice answer
:)
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