if(m-2,2m+1)lies on the graph of equation 2x+3y-10=0 find the value of m
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Answer:
Step-by-step explanation:
Given:-
(m-2,2m+1)lies on the graph of equation 2x+3y-10=0
To find:-
find the value of m
Solution:-
Given Point=(m-2,2m+1)
Given equation=2x+3y-10=0
Using Concept:-
If Given point lies on the graph of the given equation then It is a solution .
If it is a solution then it satisfies the given equation.
Now, Put x=m-2 and y=2m+1 in the given equation then,
=>2(m-2)+3(2m+1)-10=0
=>2m-4+6m+3-10=0
=>8m+3-14=0
=>8m-11=0
=>8m=11
=>m=11/8
Answer:-
The value of m=11/8
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