Question

if m(2,-5) is the midpoint of the line segment joining p(0,x) and q(4,0) find x​

Answer 1

Answer:

1.3

Step-by-step explanation:

pm = qm

(0-2)² + (x-5)² = (4-0)² + (0-x)² [squaring both the sides]

4 + x² + 25 - 10x = 16 + x²

29 - 10x = 16. [eliminating x²]

10x = 13

x = 1.3

Answer 2

If m(2,-5) is the midpoint of the line segment joining p(0,x) and q(4,0) then the value of x is 10.

Step-by-step explanation:

Given,

midpoint = (2,5)

segment points,

p = (0,x)

q = (4,0)

To find,

x

Formula,

Midpoint of any line segment is the half of sum of the end points of line segment.

$m_{y} = \frac{p_{y} + q_{y} }{2} \\\\\\5= \frac{x+0}{2}\\ \\\\10 = x + 0\\\\\\x= 10.$

Therefore, if m(2,-5) is the midpoint of the line segment joining p(0,x) and q(4,0) then the value of x is 10