If (m,2m+1) is a solution of the equation 3x+4y=26 find the value of m.
Answers
Answered by
8
hi
here us your solution
just put x=m and y=2m+1 in the given equation
3x+4y=26
3m+4(2m+1)=26
3m+8m+4=26
11m=22
m=2
hope it helps u.....
here us your solution
just put x=m and y=2m+1 in the given equation
3x+4y=26
3m+4(2m+1)=26
3m+8m+4=26
11m=22
m=2
hope it helps u.....
Answered by
5
So, here we have
X=m and Y= 2m+1
substituting the values for the equation :
3X+4Y=26
3(m) + 4(2m+1)=26
3m+8m+4=26
11m=26-4
11m=22
m = 22/11
m= 2
X=m and Y= 2m+1
substituting the values for the equation :
3X+4Y=26
3(m) + 4(2m+1)=26
3m+8m+4=26
11m=26-4
11m=22
m = 22/11
m= 2
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