.Show that Ah is greater than sum of the length of AB+BC+CD
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From the given figure, we have AB + BC + CD = AD [AB, BC and CD are the parts of AD]
Here AD is also the parts of AH.
According to Euclid’s axioms, the wholes is greater than the part. i.e., AH > AD
So, Length AH > sum of the length of AB + BC + CD.
Here AD is also the parts of AH.
According to Euclid’s axioms, the wholes is greater than the part. i.e., AH > AD
So, Length AH > sum of the length of AB + BC + CD.
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see upper that is some as my
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