Question

if m 2m and 3m are the sides of a triangle then what is its smallest angle ​

Answer 1

Answer:

Sides of the triangle = m, 2m, 3m

They are in the ratio 1:2:3

Thus, angles are also in the ratio 1:2:3

Let the angles be n°, 2n° and 3n°

Smallest angle = n°

We have

n° + 2n° + 3n° = 180°

=> 6n° = 180°

=> n° = 30°

Hence, smallest angle = 30°

Hope this helps...

Answer 2

Given :

• First side of triangle = m
• Second side of triangle = 2m
• Third side of triangle = 3m

To Find :

• The Smallest side of the Triangle

Solution :

We know that,

⠀⠀⠀⠀★ Sum of all the sides = 180

⟶⠀Sum of all the sides = 180

⟶⠀m + 2m + 3m = 180

⟶⠀m + 5m = 180

⟶⠀6m = 180

⟶⠀m = 180/6

⟶⠀m = 30

Therefore :

• First side = m = 30
• Second side = 2m = 60
• Third side = 3m = 90

Thus the smallest side is 30

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