Question

If m=4, n=1, m>n, then the Pythagorean triplet is __________ *​

Answer 1

Condition for constructing Pythagorean triples:

When m and n are any two positive integers (m<n):

a=n^2 −m^2

b=2nm

c=n^2 +m^2

Then a,b and c are Pythagorean triple

Here m=4 and n=8

∴8 ^2 −4 ^2

⇒64−16=48

∴b=2×8×4=64

∴c=8 ^2 +4 ^2

⇒64+16=80

Hence, Pythagorean triples are 48,64,80.

Answer 2

Answer:

Pythagoras triples are

A= 48

B =64

C=80

Step-by-step explanation:

Condition for constructing Pythagoras triples :

When m and n are any two positive integers ( m < n)

A = n² - m²

B = 2nm

C = n² + m²

Then a, b and C are Pythagoras triples

Here m = 4 and n = 8

∴ 8² - 4²

= 64 - 16

= 48

∴ b = 2 ⛌ 8 ⛌ 4

= 64

∴ C = 8² + 4²

= 64 + 16

= 80

Hence, Pythagoras triples are 48, 64 and 80