if m and n are the roots of the equation2x^2-4x+1=0. Find the value of (m+n)^2+4mn
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Answered by
2
HI !
p(x) = 2x² - 4x + 1
m and n are roots of p(x)
sum of roots = m + n = -b/a = -(-4)/2 = 2
product of roots = mn = 1/2
to find ,
(m+n)² + 4mn
(2)² + 4 × 1/2
4 + 2 = 6
(m+n)² + 4mn = 6
p(x) = 2x² - 4x + 1
m and n are roots of p(x)
sum of roots = m + n = -b/a = -(-4)/2 = 2
product of roots = mn = 1/2
to find ,
(m+n)² + 4mn
(2)² + 4 × 1/2
4 + 2 = 6
(m+n)² + 4mn = 6
Tazeenfathima:
tq u sooo much
Answered by
1
okay..
comparing the given equation with ax^2+b^x+c=0...we get,
a=2
b=-4
c=1
now,
sum of roots(m+n)=-b/a=2
product(m.n)=c/a=1/2
now,
(m+n)^2=2^2=4
4mn=4*1/2=2
so the req. andwer is:
4+2=6(ans)
....
mark it as the brainliest answer please
comparing the given equation with ax^2+b^x+c=0...we get,
a=2
b=-4
c=1
now,
sum of roots(m+n)=-b/a=2
product(m.n)=c/a=1/2
now,
(m+n)^2=2^2=4
4mn=4*1/2=2
so the req. andwer is:
4+2=6(ans)
....
mark it as the brainliest answer please
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