Question

if m and n are whole no such that m^n=121, then (m-1)^n+1=?

Answer 1

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Here's your answer...

${m}^{n} = 121 \\ {m}^{n} = {11}^{2}$
By comparison,
m = 11
n = 2
No other number can come here, as they will be fractional and not whole.
${(m - 1)}^{(n + 1)} \\ = {(11 - 1)}^{(2 + 1) } \\ = {10}^{3} \\ = 10 \times 10 \times 10 \\ = 1000$
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