Question

if m and n are zeroes of polynomial x² +(a+1)x +b then find value of a and b​

Answer 1

Answer:

${m}^{2} + (a + 1)m + b = 0 \\ \\ {n}^{2} + (a + 1)n + b = 0 \\ \\ {m}^{2} - {n}^{2} + ma - na + m - n = 0 \\ \\ (m + n) + a + 1 = 0 \\ \\ a = - m - n - 1. \\ \\ solving \: \: \: \: we \: get \\ \\ {m}^{2} +( - m - n)m + b = 0 \\ b = mn.$

Step-by-step explanation:

$a = - m - n - 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: b = mn$