Question

If m= cosA-sinA and n= cosA++sinA.show that √m/n+√n/m=2/√1-tan^A

Answer 1

⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐

GIVEN, m = cosA - sinA

n = cosA + sinA

THEREFORE,

L. H. S. = √(m/n) + √(n/m)

=>√m/√n + √n/√m

=> (m+n)/√mn

Now, substituting their values, we get :-

(cosA-sinA+cosA+sinA)/√(cosA-sinA)(cosA+sinA)

=> 2 cosA / √(cos²A-sin²A)

=> 2 cosA/√cos²A(1-sin²A/cos²A)

=> 2/√(1-tan²A) [HENCE PROVED]

⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐

Answer 2

Answer:

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