Question

If m cotA= n
find the value of
msinA- nCOSA
ncosA + msinA​

Answer 1

Answer:

mcotA=n

mcosA/sinA=n

mcosA*cosA/sinA+msinA

mcos2A+msin2A/sinA

1/sinA

=cosecA

Answer 2

Answer:

mcota=n cota =n/m

msina-ncosa /ncosa+msina

divide numerator and denominator of Sina

m-ncota / mcota+m

put the value of cot a

(m-n*n/m)/n*n/m+m

(m-n ka square/m)/n square/m+m

m square-n square/n square+m square