Question

The sum of ages of three brothers is 102. If the ratio between the first and second is 2:3 and that of second and the third brother is 5:3. Then what will be the age of the elder brother?

Answer 1

Answer:

Ratio of A:B:C = 2:3

5:3

10:15:15:9

A:B:C=10:15:9

Let their ages are 10k,15k and 9k respectively.

ATQ

10K+15K+9K=102

34K=102

K=3

Age of Elder Brother is B(15K) = 15×3=45 years.

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Answer 2

Step-by-step explanation:

Let the first age, second and third be x, y, z.

So Ratio of First Age to Second age,

=

$\frac{x}{y} = \frac{2}{3}$

x =

$\frac{2y}{3}$

So Ratio of Second Age to Third Age,

=

$\frac{y}{z} \: = \frac{5}{3}$

z =

$\frac{5}{3y}$

Therefore we come to the conclusion that,

$\frac{2y}{3} + y + \frac{5}{3y} = 102$

Therefore,

$\frac{2y^{2} + 3y + 5 }{3y } = 102$

Now Solve It And you will get the answer