Question

if m integer such that (-2)^2m = 2^9-m,then m=?​

Answer 1

Answer:m=3

Step-by-step explanation:

-2^2m is same as 2^2m

Becoz 2m will always be an even no. And so the sign of -2^2m will always be +ve

So 2m=9-m

3m=9

m=3

Answer 2

Answer:

m=3

Step-by-step explanation:

m into 2 is even. so any number to the power of an even number should be positive.

now we can write this again as 2^2m = 2^9-m

now bases are same, so 2m = 9-m

3m= 9

m = 3

hence proved