Question

If m is an any point in the interior of triangle pqr, ma,mb, mc are the perpendicular to side pq,qr,pr recpectively

Answer 1

Answer:

Area of ΔPQR$=\frac{1}{2}[PQ*AM+QR*BM+PR*MC]$

Step-by-step explanation:

If m is an any point in the interior of triangle pqr, ma,mb, mc are the perpendicular to side pq,qr,pr recpectively

Formula used:

Area of triangle $=\frac{1}{2}*b*h$ square units.

Now,

Area of ΔPQR = Area of ΔPMQ + Area of ΔQMR + Area of ΔRMP

Area of ΔPQR

$=\frac{1}{2}*PQ*AM+\frac{1}{2}*QR*BM+\frac{1}{2}*PR*MC]$

$=\frac{1}{2}[PQ*AM+QR*BM+PR*MC$

Area of ΔPQR $=\frac{1}{2[PQ*AM+QR*BM+PR*MC]$