Accountancy, asked by ankitraj6206829186, 4 months ago

If 'M' is coded as 31962, P is coded as 61653 and
O is coded as 51523, then the code for 'l will be
यदि 'M' का कोड 31962 है, P का कोड 61653 है तथा 0 का
कोड 51523 है, तब 'L' के लिए कोड होगा

A.21441
B.21442
C. 12441
D 12144​

Answers

Answered by mantu9000
0

If 'M' is coded as 31962, P is coded as 61653 and  O is coded as 51523, then the code for 'l will be:

Solution:

The pattern follow:

Put A = 1, B, 2, C = 3, ......, Y = 25, Z = 26

First two digits  ⇔ (Reverse digits), Last three digits = x^{2} +100  ⇔ (Reverse digits)

M = 31962

M = 13 (Reverse digits) ⇔ 31

13^{2} + 100 = 169 + 100 = 269 (Reverse digits) ⇔ 962

M = 31 962

P = 61653

P = 16 (Reverse digits) ⇔ 61

16^{2} + 100 = 256 + 100 = 356 (Reverse digits) ⇔ 653

P = 61 653

O =  51523

O = 15 (Reverse digits) ⇔ 51

15^{2} + 100 = 225 + 100 = 325 (Reverse digits) ⇔ 325

O =  51 523

Similarly:

L =  ?

O = 12 (Reverse digits) ⇔ 21

12^{2} + 100 = 144 + 100 = 244 (Reverse digits) ⇔ 442

O = 21 442

Hence, If 'M' is coded as 31962, P is coded as 61653 and  O is coded as 51523, then the code for 'L' will be "21442".

Thus, the required option is B).

Answered by Anonymous
0

Answer:

Choose the correct option

Explanation:

In the above given question,we are given that

A = 1, B, 2, C = 3, ......, Y = 25, Z = 26

First two digits  ⇔ (Reverse digits), Last three digits =   ⇔ (Reverse digits)

M = 31962

M = 13 (Reverse digits) ⇔ 31

= 169 + 100 = 269 (Reverse digits) ⇔ 962

M = 31 962

P = 61653

P = 16 (Reverse digits) ⇔ 61

= 256 + 100 = 356 (Reverse digits) ⇔ 653

P = 61 653

O =  51523

O = 15 (Reverse digits) ⇔ 51

= 225 + 100 = 325 (Reverse digits) ⇔ 325

O =  51 523

Similarly:

L =  ?

O = 12 (Reverse digits) ⇔ 21

= 144 + 100 = 244 (Reverse digits) ⇔ 442

O = 21 442

Hence, If 'M' is coded as 31962, P is coded as 61653 and  O is coded as 51523, then the code for 'L' will be "21442".

Thus, the required option is B).

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