Question

if m sin teta + n cos teta =p and m cos teta - n sin teta =q then prove m² + n² =p²+q²​

Answer 1

Step-by-step explanation:

Square on both sides of p as well as q, then add that will become,

m²(sin²A+cos²A)+n²(cos²A+sin²A) +2mnsinAcosA - 2nmsinAcosA = p²+q²

m²(1)+n²(1) = p²+q²

m²+n²=p²+q²

Answer 2

Answer:

mark me brainlist.ok please