Question

Zeroos of which quadratic polynomial are 4 and 3.
(A) x27x+12 (B) x2 - 7x + 12 (C) x + 78 - 12
(D) x2 - 7x - 12​

Answer 1

ANSWER

Given,

x

2

+7x+12

zeros

x

2

+7x+12=0

(x+3)(x+4)=0

x=−3,−4

verification,

sum of roots =−

a

b

=−

1

7

=−7=(−3)+(−4)

product of roots =

a

c

=

1

12

=12=−3×−4

Hence proved.

Answered By

Answer 2

Answer:

b) x²-7x+12

=x²-7x+12

=x²-4x-3x+12

=x(x-4) -3(x-4)

=(x-4)(x-3)

hence, zeroes are;

x-4=0

x=4

and,

x-3=0

x=3