If m times the mth term of an ap is equal to n times its nth term find the (m+n)th
term of the AP
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Answered by
22
Here is ur answer..........
Hope it helps!!☺☺
Hope it helps!!☺☺
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Answered by
1
Answer: 0
Step-by-step explanation:
given that
m*mth term of an A.P = n* nth term of an A.P
let an A.P. with first term a and difference d
then
⇒m*[a+(m-1)*d]=n*[a+(n-1)*d]
⇒am+(m-1)*md=an+(n-1)*nd
⇒am-an=d[-(m-1)*m+(n-1)*n]
⇒a(m-n)=d[-m²+m+n²-n]
⇒a(m-n)=d[n²-m²+m-n]
⇒a(m-n)=d[(n-m)(n+m)+(m-n)]
⇒a(m-n)=d(m-n)[-(n+m)+1]
⇒a= -d[m+n-1] -------------- 1
now we have to find out the value (m+n)th term
we know
(m+n)th term of an A.P. = a+(m+n-1)*d
by putting the value of a from equation 1
⇒ -d[m+n-1] +(m+n-1)*d
=0
so (m+n)th term of this A.P. will be 0.
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