Question

If magnitude of two vectors are 3 and 5 and magnitude of the scalar product is 9 then angle between the given two vectors is

Answer 1

Let a=3. B=5

A.b= |a| |b| cos tuta

9=3 × 5cos tuta

9= 15 cos tota

9/15=cos tuta

3/5= cos tita

Tuta = cos inverce 3/5