Question

If mass of a planet is eight times of the mass of the earth and it's radius is twice the radius of the ascape velocity for that planet?

Answer 1

ans is 15.8193
escape velocity = √2GM/r^2
let escape velocity of earth = √2Gm/r^2 (1)
so , escape velocity of planet = √G16m/4r^2 (2)

so , 2/1
= (√G16m/4r^2)/(√2Gm/r^2)
= √2
so √2 × escape velocity of earth
√2 × 11.186
= 15.8193

Answer 2

Answer:

ANS given above

Explanation:

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