Question

If mass of body is increased by 20% and its speed is decreased by 20% then percentage decrease in magnitude of its momentum will be °/°​

Answer 1

Answer:

4%

Explanation:

for example m = 100 v = 100

mv=100*100=10000

THerefore 120*80=9600

That means 4%

Answer 2

Given : mass of body is increased by 20% and its speed is decreased by 20%  

To Find : percentage decrease in magnitude of its momentum

Solution:

Mass = m kg

Velocity  = v  m/s

Momentum P  = mv  kgm/s

mass of body is increased by 20%  = m + (20/100)m = 1.2m  kg

speed is decreased by 20%   = v - (20/100)v = 0.8v m/s

Momentum  P'  = 1.2m * 0.8v  = 0.96mv  kgm/s

P' = 0.96P  

Decrease = P - P'  = P - 0.96P = 0.04P

percentage decrease in magnitude = (0.04P/P) * 100 = 4 %

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