Question

IF mass of cork is 50gm and velocity given by badminton player is 20 metre per square then , find the momentum transfer by badminton player​

Answer 1

velocity just before hitting the bat is-

$v1 = \sqrt{2gh} \\ = \sqrt{2 \times 10 \times 20} \\ = 20m/s$

velocity of ball just leaving the bat-

$v2 = \sqrt{2gh} \\ = \sqrt{2 \times 10 \times 45} \\ = 30m/s$

force applied by bat = rate of change of momentum

$= 200 = \frac{m(v1 - v2)}{t} \\ t = \frac{m(30 + 20)}{200} \\ = \frac{50 \times {10}^{ - 2} = \times 50 }{200} \\ = \frac{1}{4} sec$

hope this helps!

brainliest plz!