Question

If maximum percentage errors in measurement of
length, mass and time are 2%, 1% and 1%
respectively then maximum percentage error in
kinetic energy will be
(1) 1%
(2) 4%
(3) 7%
(4) 5%​

Answer 1

Answer:

(3) 7%

Explanation:

KE = ML^2T^(-2)

∆L/L% = 2; ∆M/M% = 1 ; ∆T/T% = 1

now....

∆E/E% = (∆M/M%) + 2(∆L/L%)+2 (∆T/T%)

∆E/E% = 1 + 2(2) + 2(1) = 7%

Answer 2

ANSWER

7%

Explanation

KE=ML^2T(-2)

∆M/M%=1,∆L/L%=2,∆T/T%=2

∆E/E%=1(∆M/M%)+2(∆L/L%)+2(∆T/T%)

=1(1)+2(2)+2(1)

=1+4+2

=7