Question

If maximum percentage errors in measurement of
length, mass and time are 2%, 1% and 1%
respectively then maximum percentage error in
kinetic energy will be
(1) 1%
(2) 4%
(3) 7%
(4) 5%​

Answer 1

Answer:

7%

Explanation:

K.E.= 1/2 MV²

max error in K.E. is equal to max erroe in mass plus 2 times of max erroe in velocity

max erroe in mass 1% given

max % erroe in V is not given

we can find it using

V= length÷time

so error in V = 2%+1%

             =3%

hence

max error in K.E. is

    = 1%+2×3%

   = 7%