Question

If median and mode of a distribution are 14 and 10 respectively, then mean is

Answer 1

Answer:

we know 3median = 2 mean + mode (empirical formula)

therefore, 2mean = 3median - mode

2 mean = 3(14) - 10

2 mean = 42-10

2mean = 32

mean = 16

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Answer 2

Given,

Median of a particular distribution = 14

Mode of the distribution = 10

To find,

The mean value of the distribution.

Solution,

We can simply solve this mathematical problem using the following process:

Let us assume that the mean value of the distribution is equal to x.

Mathematically,

For any particular distribution,

(Mode) = 3(median) - 2(mean)

=> (Mean) = {3(median) - (mode)}/2

{Equation-1}

Now, according to the equation-1;

(Mean) = {3(median) - (mode)}/2

=> x = {3(14) - (10)}/2

=> x = {42-10}/2 = 32/2 = 16

=> x = 16

=> the mean value of the distribution = 16

Hence, the mean value of the distribution is equal to 16.