If median salary of 100 employees of a factory is ₹24800, then find the missing frequencies f1 and f2 in the given distribution table :
Salary (in ₹) no. Of employees
10000-15000 18
15000-20000 f1
20000-25000 f2
25000-30000 15
30000-35000 12
35000-40000 22
Pls tell me how to solve it
ans. f1=8 and F2=25
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Classes F cf
10000-15000 18 18
15000-20000 f1 18+f1
20000-25000 f2 18+f1+f2
25000-30000 15 33+f1+f2
30000-35000 12 45+f1+f2
35000-40000 22 67+f1+f2
Since the median salary is ₹24800 the median class is 20000-25000
Since the no: of employees is 100,
18+f1+f2+15+12+22=100
f1+f2=100-67
f1+f2=33
f1 = 33- f2
n/2=100/2=50
l=20000
h=5000
cf=18+f1
f=f2
Just substitute these values to the median formula and voila you will have the answers to the question
You will have to use linear equation in two variables to get the answer
Hope this is helpful to you and please can you marks this as the brainliest!!
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