Math, asked by tejasy052, 6 months ago

if Meena gives an interest of rupees 45 for 1 year at 9% rate P. a...what is the sum she has borrowed​

Answers

Answered by thebrainlykapil
60

Question :-

  • If Meena gives an interest of rupees 45 for 1 year at 9% rate P. a...what is the sum she has borrowed.

 \\  \\

Given :-

  • Simple Interest = Rs,45
  • Time = 1 year
  • Rate = 9%

 \\  \\

To Find :-

  • What is the sum or Principal ?

 \\  \\

Solution :-

 \\

{:} \longrightarrow \sf\boxed{\sf{Simple \: Interest \: = \:\dfrac{Principal \: \times \: Rate \: \times \: Time}{100 }  }}\\

{:} \longrightarrow \sf{\sf{45\: = \:\dfrac{Principal \: \times \: 9 \: \times \: 1}{100 }  }}\\

{:} \longrightarrow \sf{\sf{ \dfrac{45 \:  \times  \: 100}{9 \:  \times  \: 1} \: = \:Principal}}\\

{:} \longrightarrow \sf{\sf{ \dfrac{4500}{9 } \: = \:Principal}}\\

{:} \longrightarrow \sf{\bf{ Rs,500 \: = \:Principal}}\\

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So, Principal is Rs, 500

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 \\

Verification :-

{:} \longrightarrow \sf{\sf{Simple \: Interest \: = \:\dfrac{Principal \: \times \: Rate \: \times \: Time}{100 }  }}\\

{:} \longrightarrow \sf{\sf{45\: = \:\dfrac{500 \: \times \: 9 \: \times \: 1}{100 }  }}\\

{:} \longrightarrow \sf{\sf{45\: = \:\dfrac{5 \cancel{00} \: \times \: 9 \: \times \: 1}{1 \cancel{00} }  }}\\

{:} \longrightarrow \sf{\sf{45\: = \:5  \:  \times  \: 9  }}\\

{:} \longrightarrow \sf{\bf{45\: = \: 45 }}\\

Hence, Proved

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tejasy052: Thanks
Answered by Ladylaurel
14

Answer ::

The sum Meena has borrowed is Rs. 500

Step-by-step explanation ::

To Find :-

  • The sum of money Meena borrowed

Solution :-

Given that,

  • Simple interest = Rs. 45
  • Time = 1 year
  • Rate = 9% per annum

As we know that,

\dag \: \: \boxed{\tt{Principal} \: \bf{\dfrac{ = Simple \: Interest \times 100}{Rate \times Time}}}

Where,

  • P = Principal
  • T = Time
  • S.I. = Simple interest
  • R = Rate

According the question,

\sf{\hookrightarrow \: Principal =\dfrac{45 \times 100}{9 \times 1}} \\ \\ \\ \sf{\hookrightarrow \: Principal =\dfrac{4500}{9 \times 1}} \\ \\ \\\sf{\hookrightarrow \: Principal = \dfrac{4500}{9}} \\ \\ \\ \sf{\hookrightarrow \: Principal =\cancel{\dfrac{4500}{9}}}

Answer) P = 500 ★

Therefore, the principal is Rs. 500.

Additional information

Some important formulas related to Simple interest :-

  • Simple interest \sf{= \dfrac{Principal \times Rate \times Time}{100}}

  • Principal \sf{= \dfrac{Simple \: Interest \times 100}{Rate \times Time}}

  • Rate \sf{= \dfrac{Simple \: Interest \times 100}{Principal \times Time}}

  • Time \sf{= \dfrac{Simple \: Interest \times 100}{Principal \times Rate}}
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