If Michael Jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time?
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The take off speed would be 5m/sec
As u.u = 2*9.8*1.29 = 25
So initial speed or take off speed would be 5m/sec
And the change time will be
5/9.8= 0.5 second
As u.u = 2*9.8*1.29 = 25
So initial speed or take off speed would be 5m/sec
And the change time will be
5/9.8= 0.5 second
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