Question

if mode alpha2 -beta 2 =7/4,where alpha beta are roots of equation 2x2 +7x +c =0 then value of c is

Answer 1

| a² - ß² | = 7/4

a and ß are the roots of 2x² + 7x + c = 0
so, a + ß = -7/2
a.ß = c/2

now,

| (a + ß)( a -ß ) | = 7/4

-7/2 × ( a - ß ) = ±7/4

-7/2 × √( 49/4 - 4c/2) = ±7/4

-7/4 × √(49-8c) = ±7/4

- √(49-8c) = ± 1

take square both sides

49 - 8c = 1

c = 48/8 = 6

c = 6

Answer 2

Step-by-step explanation:

hey it is your answer mate