If Mohan rolls the Die twice, then find the probability of getting a sum total of 6.
Answers
Answered by
0
Answer:
If the first roll is a 1, there are six possibilities for the second roll, but only one (a roll of 6) gives a sum greater than 6. If the first roll is a 2, there are again six possibilities for the second roll, but only two (a roll of 5 or 6) gives a sum greater than 6. And so on, giving a total of 6 x 6 = 36 possible outcomes, with 1 + 2 + 3 + 4 + 5 + 6 = 21 having a sum greater than 6. Hence the probability of a sum greater than 6 is 21/36 = 7/12 = 0.58333… (repeating decimal).
Similar questions
English,
13 hours ago
World Languages,
13 hours ago
Geography,
13 hours ago
History,
1 day ago
Physics,
8 months ago