The angular speed of a flywheel changes from 10rad/sec to 20rad/sec in5 seconds when a torque of 20 N.m is applied to it. Calculate the M.I of the flywheel
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Answer:
10 kg.m²
Explanation:
∝ = (w₂-w₁)/time = (20rad/sec-10rad/sec)/5 s = 10/5 rad/sec² = 2rad/sec²
then, torque = M.I.×∝ M.I. = Moment of Inertia,
⇒M.I. = torque/∝ ∝=Angular accleration
⇒M.I. = 20/2 kg.m²
⇒M.I. = 10 kg.m²
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