If momentum p, area A, and time T are taken as fundamental quantities, then we're the dimensional formula of energy
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Answer:
d ) (P^1 A^1/2 T^–1)
Explanation :
We know that ,
Dimensions of Energy = ML^2T^-2 ------------ (1st)
MOmentum = MLT-1 or P = MLT-1 where (P is momentum) -------- (a)
Area = L^2 or A^1/2 = L ---------(b) (where A is area)
Using a,b in 1st , we get
Dimensions of Energy = P ^1 A^1/2T^-1
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