If MP=NQ prove that triangle S OMP and ONQ are congruent and hence prove that MN and PQ bisect each other at O.
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Given data
1. MP=NQ
∠MPO =∠NQO =90°
2. In ΔMPO and ΔNQO
∠MPO =∠NQO (because each angle is 90°)
∠MOP =∠NOQ (vertical opposite angle)
MP= QN (Given)
ΔMPO ≅ ΔNQO (by AAS method)
3. So
MO = ON (by cpct) ...1)
and
PO = OQ (by cpct) ...2)
From equation 1) and equation 2), it is clear that line PQ
and line MN bisect each other.
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