Question

If (mx + 7) (5x + n) = px2
+ 15x + 14, x R then m + n + p = ?​

Answer 1

Answer:

(mx + 7) (5x + n) = px2 + 15x + 14

5mx2+mnx+35x+7n=px2+15x+14(5m)x2+(mn+35)x+7n=px2+15x+14We get5m=p; mn+35=15; 7n=145m=p;mn=−20; n=25m=p; m(2)=−20; n=25m=p; m=−10; n=25(−10)=p; m=−10; n=2p=−50; m=−10; n=2m+n+p=−10+2−50=−58

Step-by-step explanation:

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