if mx^m-nx^n=0, then what is the value of 1/x^m+x^n + 1/x^m-x^n
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Since x is nearly equal to one
Let x=1+h
h<<<1 ------(i)
Substituting in the equation we get
m−n
mx
m
−nx
n
=
m−n
m(1+h)
m
−n(1+h)
n
=
m−n
m(1+mh)−n(1+nh)
------since h<<<1
=
m−n
m−n+(m
2
−n
2
)h
=1+
m−n
(m
2
−n
2
)h
=1+(m+n)h
=(1+h)
m+n
=x
m+n
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