Question

*If (n + 1)! = 12[(n - 1)!], then find the value of n.*

1️⃣ 0
2️⃣ 2
3️⃣ 3
4️⃣ 4​

Answer 1

Answer:

(n+1) (n) (n-1)! = 12 (n-1)!

n^2 + n -12 = 0

n^2 + 4n - 3n - 12 = 0

( n - 3 ) ( n + 4 ) = 0

so n cant be negative ..

so . n = 3

Answer 2

Step-by-step explanation:

this is required solution of this question.

Om sai ram