Question

If{n+1)! = 30x(n-1)! then find the value of n.

Answer 1

Answer:

n = 5, -6

Step-by-step explanation:

(n+1)! = 30x(n-1)!

$\frac{(n + 1)!}{( n- 1)!} \: = \: 30 \\ n(n + 1) \: = 30 \\ {n}^{2} + n - 30 = 0 \\ {n}^{2} + 6n - 5n - 30 = 0 \\ n(n + 6) -5 (n + 6) \: = \: 0 \\ n = 5 \: or \: - 6$

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