Question

If (n+1)! (factorial) =120 then find the value of n.​

Answer 1

Answer:

(n+1)! =120

=5×4×3×2×1

(n+1)! =5!

which implies that n+1=5

n=5-1=4

value of n =4

Answer 2

The value of n is 3.

We can start by finding the value of n+1 using the given equation, and then subtracting 1 from it to get the value of n.

(n+1)! = 120

We know that 120 = 5 × 4 × 3 × 2 × 1,

so we can write:

(n+1)ng both sides by 5, we get:

(n+1)!/5 = 4 × 3 × 2 × 1

Simplifying the right-hand side, we get:

(n+1)!/5 = 4!

Using the definition of factorial, we know that:

4! = 4 × 3 × 2 × 1

So, we can write:

(n+1)!/5 = 4 × 3 × 2 × 1

Canceling out the common factors, we get:

(n+1) = 4

Therefore, n = (4-1) = 3.

Hence, the value of n is 3.

For similar question on factorization.

https://brainly.in/question/12745941

#SPJ3