If (n+1)! (factorial) =120 then find the value of n.
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Answered by
14
Answer:
(n+1)! =120
=5×4×3×2×1
(n+1)! =5!
which implies that n+1=5
n=5-1=4
value of n =4
Answered by
0
The value of n is 3.
We can start by finding the value of n+1 using the given equation, and then subtracting 1 from it to get the value of n.
(n+1)! = 120
We know that 120 = 5 × 4 × 3 × 2 × 1,
so we can write:
(n+1)ng both sides by 5, we get:
(n+1)!/5 = 4 × 3 × 2 × 1
Simplifying the right-hand side, we get:
(n+1)!/5 = 4!
Using the definition of factorial, we know that:
4! = 4 × 3 × 2 × 1
So, we can write:
(n+1)!/5 = 4 × 3 × 2 × 1
Canceling out the common factors, we get:
(n+1) = 4
Therefore, n = (4-1) = 3.
Hence, the value of n is 3.
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